If PQR is the tangent to a circle at q whose centre is O, AB is a chord parallel to PR and angle BQR = 70 degree, then find angle AQM.
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Answered by
173
Given:
PQR is a tangent
AB II PR
angle BQR = 70
so ∠BAQ = ∠BQR = 70 ( alternate angles)
and ∠ABQ = ∠BQR = 70 ( as AB II PR)
by summing all the angles
∠BAQ + ∠ABQ +∠AQB= 180
∠AQB = 180 - 70 -70
= 40
PQR is a tangent
AB II PR
angle BQR = 70
so ∠BAQ = ∠BQR = 70 ( alternate angles)
and ∠ABQ = ∠BQR = 70 ( as AB II PR)
by summing all the angles
∠BAQ + ∠ABQ +∠AQB= 180
∠AQB = 180 - 70 -70
= 40
Answered by
43
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