Two metal pieces having a potential difference of 800 V are 0.02 m apart horizontally. A particle of mass 1.96*10^-15 kg is suspended in equilibrium between the plates. If e is the elememtary charge, then charge on the particle is what?
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Answered by
33
The question is not clear if gravity is involved...
Force of gravity opposes the electric force due to field in between two metal pieces.. The metal pieces are vertically one above another.
Force = E q = 800/0.02 * q = mg = 1.96 *10^-15 * 10
q = 2.5 e
is the problem correctly stated ?
Force of gravity opposes the electric force due to field in between two metal pieces.. The metal pieces are vertically one above another.
Force = E q = 800/0.02 * q = mg = 1.96 *10^-15 * 10
q = 2.5 e
is the problem correctly stated ?
Answered by
38
In equilibrium,F=qE=(ne)v/d =mg
n=mgd/eV=1.96×10^-15×9.8×0.02÷1.6×10^-19×800=3
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