if pqrs is a cyclic parallelogram (having all four vertices on a circle) then (angle p)+(angle q/2)+(angle/3)+(angle s/5) = how much?
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Answer:
Opposite angles in a cyclic quadrilateral add to 180°'
('Cyclic quadrilateral' just means that all four vertices are on the circumference of a circle.) ... Thus the two angles in ABC marked 'u' are equal (and similarly for v, x and y in the other triangles.)
Step-by-step explanation:
A cyclic quadrilateral is any four-sided geometric figure whose vertices all lie on a circle. All rectangles are cyclic, but many other quadrilaterals are not. In a cyclic quadrilateral, the sum of each pair of opposite angles is 180 degrees.
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