Question

if present cost of a machine is 100000 and its value depreciates by 10 percent per annum then find the cost of the machine
A ₋ After 2 years
B₋ BEFORE 2 YEARS

Answer 1

Answer:

A- P[1+R/100]^n

=10000[1+10/100]^2

=10000[11/10]^2

=10000×121/100

=1210000/100

=12100

B-P[1-R/100]^n

=10000[1-10/100]^2

=10000[9/10]^2

=10000×81/100

=810000/100

=8100

Answer 2

Answer:

A. after 2 years,

= 89000.00Rs

B. before 2 years,

=112359.50Rs

Step-by-step explanation:

A. after 2 years,

{100000 - (100000*10/100) - (100000*10/100*10/100) } Rs

= {100000 - 10000 - 1000 }Rs

= 89000Rs

B. before 2 years,

x -(x*10/100)-(x*10/100*10/100)=100000Rs

or, x ( 1 - 10/100 - 10/100*10/100)=100000Rs

so, x {( 100-10-1)/100} =100000Rs

thus, x = 100000Rs *100/89

thus, x = 112359.551Rs