If probability of getting a head is 0.56 find the probability of tail
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When we toss a coin, there are two possible outcomes: head and tail.
So P(head) + P(tail) = 1
Given that probability of getting a head = 0.56
P(head) = 0.56
P(tail) = 1 - P(head) = 1 - 0.56 = 0.44
Probability of getting a tail is 0.44
So P(head) + P(tail) = 1
Given that probability of getting a head = 0.56
P(head) = 0.56
P(tail) = 1 - P(head) = 1 - 0.56 = 0.44
Probability of getting a tail is 0.44
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There are only 2 possible outcomes when a coin is tossed viz Head and tail.
sum of all probabilities is always 1
P(H)+ P(T)= 1
Probability of getting tail= 1-prob. of getting head
=1-0.56=0.44
;)
sum of all probabilities is always 1
P(H)+ P(T)= 1
Probability of getting tail= 1-prob. of getting head
=1-0.56=0.44
;)
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