Question

If projectile is projected with an angle" ∅ " at velocity of "u" from the top of the building which has height of "H" from the ground then how to calculate the time taken to reach the ground ?

Answer 1

time interval is

$\frac{u \sin( \alpha ) \sqrt{ {u}^{2} { \sin( \alpha ) }^{2} + 2g h } }{g}$