Question

if pt (2,-3),(a,-1),(0,4),are collinear ,find value of a​

Answer 1

Step-by-step explanation:

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Answer 2

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if pt (2,-3),(a,-1),(0,4),are collinear ,

find value of a????

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• the points (2,-3),(a,-1),(0,4) will be colinear if the area constructed by these points is zero...
• as they it is given that the points are colinear so the area enclosed by these points is zero....

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value of a=5

$\:\: \underline{\underline{\bf{\large\mathfrak{~~solution~~}}}}$

$\:\: \underline{\underline{\bf{\large\mathfrak{formula\: used}}}}$

the area of a triangle of vertices (x1,y1),(x2,y2),and (x3,y3)is

$= \frac{1}{2} (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2))$

therefore....

$\:\: \underline{\underline{\bf{\large\mathfrak{the\: equation}}}}$

$= > \frac{1}{2} (2( - 1 - 4) + a(4 - 2) + 0( - 3 + 1)) = 0 \\ = > \frac{1}{2} ( - 10 + 2a) = 0 \\ = > - 5 + a = 0 \\ = > a = 5$

$\:\: \underline{\underline{\bf{\large\mathfrak{conclusion}}}}$

the value of a=5

$\:\: \underline{\underline{\bf{\large\mathfrak{Hope\: this\: helps \:you\:......}}}}$