If pth term is 1/q and qth term is 1/p then find the sum of pq terms
Answers
Answered by
7
First Of All, Welcome To The Biggest Learning Platform For The World wide Students.
Answer. Given pth term = 1/q That is ap = a + (p - 1)d = 1/q aq + (pq - q)d = 1 --- (1) Similarly, we get ap + (pq - p)d = 1 --- (2) From (1) and (2), we get aq + (pq - q)d = ap + (pq - p)d aq - ap = d[pq - p - pq + q] a(q - p) = d(q - p) Therefore, a = d Equation (1) becomes, dq + pqd - dq = 1 d = 1/pq Hence a = 1/pq Consider, Spq = (pq/2)[2a + (pq - 1)d] = (pq/2)[2(1/pq) + (pq - 1)(1/pq)] = (1/2)[2 + pq - 1] = (1/2)[pq + 1].
ThankYou Mark It As Brainliest My Friend, If You Find it useful
Answer. Given pth term = 1/q That is ap = a + (p - 1)d = 1/q aq + (pq - q)d = 1 --- (1) Similarly, we get ap + (pq - p)d = 1 --- (2) From (1) and (2), we get aq + (pq - q)d = ap + (pq - p)d aq - ap = d[pq - p - pq + q] a(q - p) = d(q - p) Therefore, a = d Equation (1) becomes, dq + pqd - dq = 1 d = 1/pq Hence a = 1/pq Consider, Spq = (pq/2)[2a + (pq - 1)d] = (pq/2)[2(1/pq) + (pq - 1)(1/pq)] = (1/2)[2 + pq - 1] = (1/2)[pq + 1].
ThankYou Mark It As Brainliest My Friend, If You Find it useful
Answered by
1
Answer:
Step-by-step explanation:
yes he or she is right
Similar questions