if pth term of a HP is qr and its qth term is pr then its rth term is
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Using the usual symbols, a+(p−1)d=qa+(p−1)d=q and a+(q−1)d=a+(q−1)d=p. Subtracting, (p−q)d=q−p(p−q)d=q−p and so long as pp is not qq, d=−1d=−1 from which a=q+p−a=q+p−1. But that is not term nn. Term nn is p+q−1+(n−1)(−1)=p+q−n
khushi0712:
thnx
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