Question

If pth term of an ap is q and qth term is p then find its p q th term

Answer 1

this is Ur required result

Answer 2

Answer:

0

Step-by-step explanation:

Ap=Q=a+(p-1)d.......(1)

Aq=P=a+(q-1)d........(2)

Subtracting equation (1)&(2),

=>Ap-Aq=[a+(p-1)d]-[a+(q-1)d]

=>q-p=a+(p-1)d-a-(q-1)d

=>q-p=a-a+pd-d-qd+d

=>q-p=pd-qd

=>q-p=(p-q)d

=>q-p=[-(q-p)d]

=>d= (q-p)/[-(q-p)]

=>d=-1

Now,

putting the value of d in equation (1)

=>Ap=a+(p-1)(-1)

=>q=a+(p-1)(-1)

=>q=a-p+1

=>a=(q+p-1)

Again,

Ap+q=a+(p+q-1)d

By putting the value of d and a, we get,

=>Ap+q=q+p-1+(p+q-1)(-1)

=>Ap+q= q+p-1-p-q+1

=>Ap+q=0

Therefore the answer is 0.

Hope it's helpful

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