Question

If Q(0,1) is equidistant from P(5,-3) and R(x,6), find the values of x.Also find the dustances QR and PR

Answer 1

Here since R is equidistance from Q and P
Therefore QR = PR
Now first of all find QR
= under root x square + 25 ( eqa 1)
now find PR
= under root x square + 25 - 10x +81 (equ 2)
now equate them
under root x square + 25 = under root x square + 25 - 10 x + 81
10x - 81 = 0
x = 81/10
now find PR and QR by putting formula

Answer 2

$\textbf{Answer is in Attachment !}$