Question

if Q(0,1) is equidistant from P(5,-3) and R(x,6) , find the values of x. Also find the distances QR and PR.



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Answer 1

Answer:

Step-by-step explanation:

ᴛʜᴇ ᴀɴsᴡᴇʀ ɪs ᴏɴ ᴘɪᴄ.

Answer 2

Answer:

if Q(0,1) is equidistant from P(5,-3) and R(x,6) , find the values of x. Also find the distances QR and PR.

Step-by-step explanation:

by using equidistance QP=QR

$\sqrt{(5-0)^2+(-3-1)^2} =\sqrt{(x-0)^2+(6-1)^2}\\25+16=x^2+25\\x^2=16\\x=4,-4$

Now

QP is

$\sqrt{25+16}\\ =\sqrt{41}$

PR is

$\sqrt{(5-x)^2+(-3-6)^2}\\\sqrt{81+1}\\\sqrt{82}$