Question

If q-1, q+3,3q-1 are in ap then q is equal to

Answer 1

Answer:

q=4.hope this will help you out

Answer 2

$We \:know \:that ,$

$If \: a, \: b , \:and \: c \: are \: in \:A.P \:then$

$\boxed{\pink{b-a = c - b }}$

$Given, (q-1),(q+3)\:and \:(3q-1) \: are \: in \:A.P$

$Here , a = q-1 , \: b = (q+3) \:and \: c = (3q-1)$

$(q+3)-(q-1) = (3q-1)-(q+3)$

$\implies q+3-q+1 = 3q-1-q-3$

$\implies 4 = 2q - 4$

$\implies 4 + 4 = 2q$

$\implies 8 = 2q$

/* Dividing each term by 2 , we get */

$\implies \frac{8}{2} = \frac{2q}{2}$

$\implies 4 = q$

Therefore.,

$\red{ Value \: of \:q}\green{ = 4}$

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