Question

If q= 2t square 3 find current at t=2sec​

Answer 1

$\huge{\underline{\underline{\sf{Answer :}}}}$

From the Question,

$\sf{q = 2t{}^{2} + 3}$

To find the current flowing through the conductor at t=2sec

We know that,

$\sf{I = \frac{dq}{dt}}$

$\implies \: \sf{l = \frac{(2t{}^{2} + 3) }{dt} }$

Differentiating q w.r.t to t,we get:

$\implies \: \boxed{\sf{l = 4t}}$

If t = 2s,

$\implies \: \sf{l = 8 \: ampere}$

At t = 2s,current of magnitude 8A flows through the conductor

Answer 2

$\huge{\bold{\underline{\underline{.........Answer.........}}}}$

$\huge{\bold{\underline{Given:-}}}$

${dq = 2t^{2} + 3}$

$\huge{\bold{\underline{Explanation:-}}}$

we know,

${I = \frac{dq}{T}}$

For small interval of time(dt).

${dI = \frac{dq}{dt}}$

Substituting the values.

${dI = \frac{2t^{2} + 3}{dt}}$

Differentiating gives,

${dI = 4t}$

As 3 is constant when differented it gives zero.

if t = 2s.

then,

I = 4 × 2

I = 8 amperes.

$\huge{\boxed{\boxed{ I = 8 \: amperes}}}$

so,the current flowing is 8 amperes.