IF Q and 2Q-45° are acute angles such that sinQ=cos(2Q-45°) then tanQ is
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Answer:
tanQ=1
Step-by-step explanation:
first we put the value of 0,30,45,60 and 90 in sinQ=cos (2Q-45)
from this we get for 45° LHS=RHS
So our required angle is 45
therefore tanQ would be 1
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