If q cos0=p,find tan 0-cot0 in terms of p and q..
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Answer:
cos =B/H
p/q = B=p
h=q
By Pathogorus theorems H2=p2+B2
q2=x+p2 [ all p 2 Or q 2 are a squre ]
q2-p2 =x 2
x=√q2-p2
Tan=P/B , cos =B/P
tan0 - cos0
√q2 -p2/P - q/√q2-p2
Ans. q2-q2 - √q2-p2 / p√q2-p2
I hope it will help you didi
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