Math, asked by anoosh96, 10 months ago

if q is directly proportional to square of (p-1) and q=20 when p= 3 find the value of P when q = 80​

Answers

Answered by 2009anay19
3

Answer:

9

Step-by-step explanation:

q∝(p-1)(2)

q=20 when p=3

20=k(3-1)(2)

k= proportionality constant

20=4k

20/4=k

k=5

------------

q=80

p=?

80=k(p-1)(2)

80=5(p-1)(2)

80=10(p-1)

80/10=p-1

8=p-1

p=8+1

p=9

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Answered by vishal15116
6

Step-by-step explanation:

q=k(p-1)^2

20=k(3-1)^2

20=k×4

k=5

when q = 80

q=k(p-1)^2

80=5(p-1)^2

80=5(p^2-2p+1)

p^2-2p-15=0

(p-5)(p+3)=0

p=5

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