if q is directly proportional to square of (p-1) and q=20 when p= 3 find the value of P when q = 80
Answers
Answered by
3
Answer:
9
Step-by-step explanation:
q∝(p-1)(2)
q=20 when p=3
20=k(3-1)(2)
k= proportionality constant
20=4k
20/4=k
k=5
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q=80
p=?
80=k(p-1)(2)
80=5(p-1)(2)
80=10(p-1)
80/10=p-1
8=p-1
p=8+1
p=9
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Answered by
6
Step-by-step explanation:
q=k(p-1)^2
20=k(3-1)^2
20=k×4
k=5
when q = 80
q=k(p-1)^2
80=5(p-1)^2
80=5(p^2-2p+1)
p^2-2p-15=0
(p-5)(p+3)=0
p=5
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