Math, asked by arundhati1158, 2 months ago

If Q is the HCF of 468 and 222 find x and y, d=468x+222y Also show that x and y are not unique.

Answers

Answered by Anonymous

1

Answer:

Hence, HCF of 468 and 222 in the form of 468x + 222y is 468 x -9 + 222 x 19.

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