Question

if QT parallel PR, angle TQR=40° FIND x and y

Answer 1

Answer:

In triangle qtr

angle qtr + angle r +40 degree = 180 degree(angle sum property of triangle)

angle x  + 130= 180

angle x 180- 130 = 50

angle x is 50

in triangle PSR

y = x +30 ( exterior angle theorm)

50+30

y = 80

Answer 2

firstly,it must be QT perpendicular PR
Now,In ∆QTR
angle QTR=90°
angle TQR=40°
Hence,using angle sum property of a triangle
angle X=180° -(90°+40°)
{angle X = 50°}
Now,In ∆PSR
Angle PSR=180°-(30° + 50°).....using A.S.P
Angle PSR= 100°
lastly,Angle Y= 180°- angle PSR.....(angle of a straight line)
hence,angle Y =80°