Question

If r=3 is a root of the quadratic equation kr~-kr-3=0,find value of k

Answer 1

I hope you'll understand the answer to the question.

Answer 2

Answer:

kr²-kr-3=0

given r=3

therefore,

k(3)²-k(3)-3=0

9k-3k-3=0

6k-3=0

k=3/6

k=1/2

hence solved

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