sinA = 3/4 find cosA and tanA
Answers
Answered by
4
hey dear
given us.
sinA = BC/AC = p/h = 3/4
from Pythagoras law
b² = p² + h²
=> b = √ 3² + 4²
= > b = √ 9 + 16
=> b = 5
so
cosA = b/h = 5/4
tanA = p/b = 3/5
given us.
sinA = BC/AC = p/h = 3/4
from Pythagoras law
b² = p² + h²
=> b = √ 3² + 4²
= > b = √ 9 + 16
=> b = 5
so
cosA = b/h = 5/4
tanA = p/b = 3/5
Attachments:
khushi250:
thank you so much
Good
Nice
Your Welcome!
:)
Similar questions