Question

if r=3,q=2×10 to the power minus 7,Q=3×10 to the power minus 7 then find force=...

Answer 1

We are going to use Coulomb's Law. Our data is:

$r = 3 \, \, m \\ \\ q = 2 \times 10^{-7} \, \, C \\ \\ Q = 3 \times 10^{-7} \, \, C$

The Force will be:

$\displaystyle F = \frac{1}{4\pi\varepsilon_{\circ}}\frac{Qq}{r^2} \\ \\ \\ \implies F = (9\times 10^9) \times \frac{3 \times 10^{-7} \times 2 \times 10^{-7}}{3^2} \\ \\ \\ \implies F = \frac{\cancel{9} \times 10^9 \times 6 \times 10^{-14}}{\cancel{9}} \\ \\ \\ \implies \boxed{\bold{F = 6 \times 10^{-5} \, \, N}}$

Thus, the Force is $\bold{6 \times 10^{-5} \, \, N}$