solve the quadratic equation by factorization and check the solutions
81x^2 - 36x + 4 = 0
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Answered by
11
Given Equation is 81x^2 - 36x + 4 = 0
= > 81x^2 - 18x - 18x + 4 = 0
= > 9x(9x - 2) - 2(9x - 2) = 0
= > (9x - 2)(9x - 2) = 0
= > (9x - 2)^2 = 0
= > 9x = 2
= > x = (2/9).
Verification:
= > 81(2/9)^2 - 36(2/9) + 4
= > 4 - 8 + 4
= > 8 - 8
= > 0.
Hope this helps!
= > 81x^2 - 18x - 18x + 4 = 0
= > 9x(9x - 2) - 2(9x - 2) = 0
= > (9x - 2)(9x - 2) = 0
= > (9x - 2)^2 = 0
= > 9x = 2
= > x = (2/9).
Verification:
= > 81(2/9)^2 - 36(2/9) + 4
= > 4 - 8 + 4
= > 8 - 8
= > 0.
Hope this helps!
siddhartharao77:
:-)
Answered by
6
81x²-36x +4 = 0
= 81x²-18x -18x +4 = 0
= 9x(9x-2) -2(9x-2)
= (9x-2)(9x-2)
hence,x = 2/9.
= 81x²-18x -18x +4 = 0
= 9x(9x-2) -2(9x-2)
= (9x-2)(9x-2)
hence,x = 2/9.
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