Physics, asked by macshubham8896, 10 months ago

If r = 4 ohm, cross-section area is 1mm^2, and length = 20m. Then find its conductivity?

Answers

Answered by Anonymous
4

\large\underline{\underline{\sf Given:}}

  • Resistance (R) = 4Ω

  • Area (A) = 1mm² or \sf{10^{-3}m}

  • Length (L) = 20m

\large\underline{\underline{\sf To\:Find:}}

  • Conductivity \sf{(\sigma)}=?

\large\underline{\underline{\sf Solution:}}

\large{\boxed{\sf Conductivity (\sigma)=\frac{1}{Resistivity (\rho)}}}

___________________________________

\large{\boxed{\sf Resistance (R)=\rho\frac{L}{A}}}

\large\implies{\sf 4=\rho\frac{20}{10^{-3}} }

\large\implies{\sf \rho=\frac{4×10^{-3}}{20} }

\large\implies{\sf \rho=\frac{10^{-3}}{5} ohm.m}

Now ,

\large\implies{\sf Conductivity (\sigma)=\frac{1}{\rho}}

\large\implies{\sf \sigma=\frac{5}{10^{-3}} }

\large\implies{\sf \sigma=5000\:siemens\:per\:meter}

\Large\underline{\underline{\sf Answer:}}

•°•Conductivity is 5000 Siemens per meter.

Similar questions