if R and H are horizontal range and maximum height attained by a projectile than its speed of projection is
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hii dear______✌️✌️✌️✌️
Range R = 2u/g
and
Max.
Height, H =u^2/2g
Divide the Range and Height we get,
R/H = 4/u
u = 4H/R m/s is the speed of projection.
thanks and regards
Ajay
B.Tech,IIT(BHU)Varanasi
Range R = 2u/g
and
Max.
Height, H =u^2/2g
Divide the Range and Height we get,
R/H = 4/u
u = 4H/R m/s is the speed of projection.
thanks and regards
Ajay
B.Tech,IIT(BHU)Varanasi
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