Math, asked by nayannarayan444, 9 months ago

if r is a real number such that l r l < 1 and if a=5(1-r), then....
0 <a< 5
5< a< 5
0< a< 10

Answers

Answered by shreeyatffs
2

Answer:

0<a<10

Step-by-step explanation:

|r| < 1 means that

-1<r<1

So,

-1<r<1

Multiplying the entire expression with 5,

-5<5r<5

Reversing the sign of the expression thus accordingly changing the equality sign also;

5>-5r>-5

Adding 5 to the entire expression,

5-5<5-5r<5+5

Taking 5 common,

0<5(1-r)<10

since, 5(1-r) =a (given)

thus, 0<a<10 (Ans)

Answered by Angelsonam
6

Answer:

\huge\boxed{\fcolorbox{red}{orange}{Answer!☺}}

Option c is correct

0< a< 10

✌✌✌Hope it will help you ☺☺☺

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