If λ ? R is such that the sum of the cubes of the roots of the equation, x2+(2−λ)x +(10−λ)=0 is minimum, then the magnitude of the difference of the roots of this equation is meritnarion
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SOLUTION :
Option (c) is correct : - 1/2
Given : x² - x = λ(2x - 1) and sum of roots is zero.
x² - x = λ(2x - 1)
x² - x = 2λx - λ
x² - x - 2λx + λ = 0
x² - (1 + 2λ)x + λ = 0
On comparing the given equation with ax² + bx + c = 0
Here, a = 1 , b = - (1 + 2λ) , c = λ
Sum of roots = - b/a
Sum of roots = - - (1 + 2λ) /1
Sum of roots = (1 + 2λ)/1
0 = (1 + 2λ)/1
[Given : Sum of roots = 0 ]
(1 + 2λ) = 0
2λ = - 1
λ = - 1/2
Hence, the value of λ is - ½.
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