Question

If ‘R’ is the horizontal range for Ɵ inclination and H is the height reached by the

projectile, show that R(max.) is given by

Rmax =4H​

Answer 1

Answer:

range = v² sin2∅ / g

for maximum range ∅ = 45°

=> R(max) = v² sin 2(45) ÷ g = (v²/g) sin 90°

=> R(max) = v²/g...............1

height = v² sin²∅ ÷ (2g)

=> height = (v²/2g) sin²(45) = (v²/2g) × (1/√2)²

=> H = (v²/2g) (1/2)

=> H = (v²/g) (1/4).........2

putting value of (v²/g) from equation 1 in equation 2

we get,

H = { R(max) } (1/4)

=> R(max) = 4H

Answer 2

Answer:

I hope above attachment helpful to you ☺️...