if r+r1+r2 = r3 then show that C =90
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Answer:
See the proof below.
Step-by-step explanation:
r1 – r = r2 + r3
∆/(s - a) - ∆/s = ∆/(s - b) + ∆/(s - c)
⇒ ∆a/s(s - a) = ∆a/((s - b)(s - c))
⇒ s(s - a) = (s - b)(s - c)
⇒ tan(C/2) = √(((s - b)(s - c))/s(s - a)) = 1
⇒ C = 90º
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