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1. An object is thrown at certain angle to the ground moves in curved path and falls back to the ground. The initial and the final position of path of an object lie on the same horizontal line. What is the work done by the force of gravity on object?
2.A force of 10 Newton acts on a body of 2kg for 3 seconds. Find the kinetic energy acquired by the body in 3 seconds?
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Answer:
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a = F/m. I need the velocity at time t = 3 seconds, u = 0 , F = 10N , m = 2kg. v = 15 m/s . Now, Kinetic energy = 1/2mv² = 1/2(2)(15)² = 15² = 225 J.
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Answer:
1) Work done by the force of gravity on the object is equal to the negative of the change of potential energy of the object.
W
g
=−ΔP.E
W
g
=−(mgh
2
−mgh
1
) OR W
g
=−mg(h
2
−h
1
)
But as the object lies on the same horizontal line of the ground i.e h
1
=h
2
=0
⟹W
g
=0
Thus work done by gravity force on the object is zero.
2) a = F/m. I need the velocity at time t = 3 seconds, u = 0 , F = 10N , m = 2kg. v = 15 m/s . Now, Kinetic energy = 1/2mv² = 1/2(2)(15)² = 15² = 225 J.
Explanation:
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