Question

If R=Rmax/2 then angle of projection is

Answer 1

here R is

$\frac{{u}^{2}sin2\theta}{g}$

and $R_max$ is

$\frac{{u}^{2}}{g}$

according to question

R=$\frac{R_max}{2}$

$\frac{{u}^{2}sin2\theta}{g}$=$\frac{\frac{{u}^{2}}{g}}{2}$

sin2θ=2

sinθ=$\frac{2}{2}$

sinθ=1

θ=45°

Answer 2

Answer: Range is maximum at 90 degree So Range/2 means it will be max at 45

Explanation: