Question

If R = {(x, y):x, y E Z, x^2 + y^2 ≤ 4} is a relation on Z, then domain of R is​

Answer 1

Step-by-step explanation:

R = { ( x , y ) : x , y € Z , x^2 + y^2 < 4 }

Domain is the set of all possible values of x .

Here the possible values of x satisfying x^2 + y^2 < 4 and x€ Z are 0 , 1 , 2

So the domain is { 0 , 1 , 2 }

Answer 2

Answer:

R = { (-2, 0) , (-1, 0) , (0, 0) , (1, 0) , (2, 0), (0, -2), (0, -1), (0, 1), (0, 2) }

D = { -2, -1, 0, 1, 2 }