if r1=36 r2=18 r3=12 then b=
Answers
Answered by
1
Step-by-step explanation:
b= r1+r2+r3
=>36+18+12
=>76
Answered by
2
Answer:
r
1
=8,r
2
=12,r
3
=24
Then we know that, In a ΔABC
r
1
=
r
1
1
+
r
2
1
+
r
3
1
r
1
=
8
1
+
12
1
+
24
1
r
1
=
24
3+2+1
r
1
=
24
6
r
1
=
4
1
r=4
Now, we know that
Δ
2
=rr
1
r
2
r
3
Δ=
rr
1
r
2
r
3
Δ=
4×8×12×24
Δ=
2×2×2×2×2×2×2×3×2×2×2×3
Δ=2×2×2×2×2×3
Δ=96
Again, we know that
r=
s
Δ
r=
s
96
4=
s
96
s=
4
96
s=24
So,
r
1
=
s−a
Δ
=
24−a
96
8=
24−a
96
24−a=
8
96
24−a=12
a=12
r
2
=
s−b
Δ
=
24−b
96
12=
24−b
96
24−b=
12
96
24−b=8
b=16
r
3
=
s−c
Δ
=
24−c
96
24=
24−c
96
24−c=
24
96
24−c=4
c=20
Hence, this is the answer.
Step-by-step explanation:
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