If R1 = 5ohm, R2 = 8ohm, R3 = 12 ohm and a 6 V battery is connected to the series arrangement. Calculate (a) the total resistance in the circuit and (b) the total current flowing in the circuit (c) voltage across 12 ohm.
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Answer:
(a) Total R= 5ohm+8ohm+12ohm
=25 ohm.
(b) Total I= V/Rs
= 6/25
=0.24A
(c) V across 12 ohm= 0.24*12
=2.88V
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