Question

If R1,R2,R3 and R4 are connected in parallel, obtain the relation of their resultant resistance
(Rp). Three resistors of resistances 20, 42, and 6 Q are connected in parallel across a
battery of 12 V. Calculate the total current flowing through the combination ​

Answer 1

Answer:

0+1

Explanation:

If R1,R2,R3 and R4 are connected in parallel, obtain the relation of their resultant resistance

(Rp). Three resistors of resistances 20, 42, and 6 Q are connected in parallel across a

battery of 12 V. Calculate the total current flowing through the combination

Answer 2

The relation for the resistors connected in parallel will be:

1/$R_{T}$ = 1/R1 + 1/R2 +1/R3 +1/R4

Resistors connected in parallel

• When the resistors are connected to each other in parallel, the resultant resistance is equal to the sum of the reciprocal of individual resistance.
• This is given by:

                          1/$R_{T}$= 1/R1 + 1/R2 +1/R3 +1/R4

Given:

R1 = 20 ohm

R2 = 42 ohm

R3= 6 ohm

Voltage = 12V

To find = Current (I)

Step- by-step calculations:

Total resistance; 1/$R_{T}$ = 1/R1 + 1/R2 +1/R3 +1/R4

1/$R_{T}$ = R2R3 +R1R3+ R1R2 /R1R2R3

1/$R_{T}$ =  252 + 120 + 840/ 5040

1/$R_{T}$= 1212/5040

$R_{T}$ = 0.24 Ohm

So, current;I = V/R

I(current) = 12/ 0.24

I = 50 ampere

Thus the current flowing through the combination is 50 ampere.