Question

if radii of circular ends of a conical bucket are 28 cm and 7 cm and height 4& cm .the capacity of bucket is

Answer 1

Here is your answer...

Let the bigger radius be R=28 cm
and the smaller radius be r=7 cm
The height h=48cm

The capacity of bucket= π/3h(R^2+r^2+Rxr)

$\frac{22}{7} \div 3 \times 48( {28}^{2} + {7}^{2} + 28 \times 7)$

=3.14/3x48(784+49+196)
=1.04x48x1029
=51367.68

Hope it's help you.