Question

If radius and height of the right circular cone is 6 and 8 find the slant height.​

Answer 1

Answer:

slant height = 10

Step-by-step explanation:

slant height = l = $\sqrt{h^{2} + r^{2} }$

           where h = height = 8 and radius = 6 = r

 therefore l = $\sqrt{6^{2} + 8^{2} }$

                    = $\sqrt{36 + 64}$

                   = $\sqrt{100$

                    = 10

Hope this helps!!!

Answer 2

The slant height of right circular cone is 10 cm.

Step-by-step explanation:

We are given with the radius(r) and height(h) of a right circular cone,

$r=6cm$

$h=8cm$

and we have to find the slant height(l) of cone.

• Formula used,

we use Pythagoras theorem by assuming right angled triangle in cone.(as we can in attached picture)

$H=\sqrt{P^{2} +B^{2} }$

Where the perpendicular(P) and base(B) of right angled triangle are Height(h) and cone radius(r) respectively and slant height(l) is the hypotenuse(H) of triangle. so the slant height (l) is,

$l=\sqrt{h^{2} +r^{2} }$

• Calculation for slant height (l)

we have

$r=6cm$

$h=8cm$

so by using formula we get,

$l=\sqrt{(8)^{2} +(6)^{2} }$

   $=\sqrt{64+36}$

    $=\sqrt{100}$

   $l=10cm$

we get the slant height of cone is 10 cm.