If radius of a circle is 20cm and distance of a chord from the centre of the circle is 15cm then the length of the chord is
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Answer: 24 cm
Step-by-step explanation:
Let the centre of the circles be A(radius 15) ,B(radius 20) and common chord is CD.
Since , 252=202+152
△ACB≅△ADB are right angle triangle . Also, AB⊥CD
Area of quadrilateral ACBD=2×Area △ACB
=2×0.5×15×20=300cm2
Again, Area of ACBD =AB×CD/2=25×CD/2=300
Therefore, CD=24 cm
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