if radius of a solid sphere is doubled, find % change in it's volume
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Answer:
700%
Step-by-step explanation:
If radius will be r.
Then, The volume of sphere = (4/3)πr*3
And, If we double the radius. i.e, 2r
Then, The volume of sphere = (4/3)π(2r*) 3
i.e, Volume of Sphere= (32/3)πr*3
Change in volume of sphere= (32/3)πr*3-(4/3)πr*3
= (28/3)πr*3
%age change= change in volume/Original Volume *100
= {(28/3)πr/(4/3)πr^3} *100= 700%
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