Question

If radius of earth become half and mass become three time, then what would will be the value of g.​

Answer 1

Explanation:

relation

$g = \frac{GM}{ {r}^{2} }$

Where. G - is gravitational constant

M - mass of earth

r. = radius of earth

New radius = r/2

New mass = 3M

Now

$g' = \frac{3GM}{( \frac{r}{2}) {}^{2} } \\ \\ = \frac{3GM}{ \frac{ {r}^{2} }{4} } \\ \\ = \frac{3GM}{ {r}^{2} } \times 4 \\ \\ = 12 \times \frac{GM}{r {}^{2} } \\ \\ g' = 12 \times (g)$

Answer 2

Answer:

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