Physics, asked by arumughan5124, 1 year ago

If radius of earth is 6400 km,What will be the weight of 1 quintal body if taken to the height of 1600 km above the sea level?

Answers

Answered by HappiestWriter012
56
We know that,
Change in acceleration due to gravity by taking to a height h above the surface g'= g/( 1 +h/R)²

Now, Acceleration at height " 1600 km " = g/ ( 1 + 1600/6400 )² = g /( 1 +1/4)²= 16g/25 = 6.272 m/s²

We know that, The weight of the body is subjected as force on the earth.
So,
W = mg

Given, m = 100 kg.

Now, Weight " W " = mg = 100(6.272) = 627.2 N.

Hope helped!
Answered by abhi178
23
formula of acceleration due to gravity at h height from the surface of earth/sea level when radius of earth is R is given by
\bold{g'=\frac{g_0}{(1+\frac{h}{R})^2}}
Here g₀ is acceleration due to gravity on sea level/earth surface

one thing we also know,
e.g., acceleration due to gravity on sea level/earth surface , g₀ = 9.8m/s²
So, g' = 9.8/(1 + 1600/6400)² [ ∵ h = 1600 km , R = 6400 km]
g' = 9.8/(1 + 1/4)² = 16 × 9.8/25 m/s²

Now, weight of body = mass of body × g'
= 100 × 16 × 9.8/25
= 64 × 9.8 = 627.2N
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