If radius of wire redusec by half then resistance will be
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R is inversely proportional to Area of the conductor.
Therefore,
R1/R2=A2/A1
= pi r1^2/ pi (r1/2)^2
=pi r1^2×4/ pi r1^2
Hence R1/R2= 4
R2 will be one fourth of R1, which is the initial resistance of the conductor.
I hope you've understood...
Therefore,
R1/R2=A2/A1
= pi r1^2/ pi (r1/2)^2
=pi r1^2×4/ pi r1^2
Hence R1/R2= 4
R2 will be one fourth of R1, which is the initial resistance of the conductor.
I hope you've understood...
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