Question

If refractive measure of water are 1.32, 1.33, 1.34, 1.35 and 1.36, then find absolute error,
relative error and percentage error.

Answer 1

Answer:

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Explanation:

Mean Absolute Error= Δamean= [Σi=1i=n |Δai|]/n

Note: While calculating absolute mean value, we dont consider the +- sign in its value.

Relative Error or fractional error

It is defined as the ration of mean absolute error to the mean value of the measured quantity

δa =mean absolute value/mean value = Δamean/am

Percentage Error

It is the relative error measured in percentage. So

Percentage Error =mean absolute value/mean value X 100= Δamean/amX100