Question

If relation between distance and time is t=ax^2+bx retardation is

Answer 1

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if , t = ax^2+bx

then, differentiate both side with respect to time (t)

dt/dt = 2ax.dx/dt + b.dx/dt

1 = 2axv + bv

v(2ax + b) = 1

(2ax + b) = 1/v

Again differentiate both side with respect to time (t)

2a.dx/dt = -v^(-2)*dv/dt

2av = v^(-2)*acceleration

acceleration = -2av³

Hence,

retardation= 2av³ (ANS)

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