Question

if relative lowering in vapour pressure is 0.5 for aqueous solution of urea then​

Answer 1

hi friend,

here is your answer

Answer:

1 mole of silver chloride (agcl)

Explanation:

The mole fraction is

i.n+N

i.n

=

i.2+3

i.2

The relative lowering in vapour pressure is

P

ΔP

=0.5=

2

1

But

P

ΔP

=mole fraction

Hence,

2

1

=

i.2+3

i.2

i=

2

3

=1.5

1.5=1+(n−1)α

α=

2

1

The number of moles of Cl

−

ions=2×

2

1

=1 moles.

Hence 1 mol of AgCl is precipitated.

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