Math, asked by bhaveshsaini560, 1 year ago

. If repetitions are not permitted

i. How many 3 digit numbers can be formed from the six digits 2, 3, 5, 6, 7 & 9?

ii. How many of these are less than 400 ?

iii. How many are even?

iv. How many are o​

Answers

Answered by santoshdukare46
10

Answer:

1) 120 2)40 3) 40 4) 80

Step-by-step explanation:

1) no Repeation allowed so ,

in 1st place there are 6 chances to sit

in 2nd place there are 5 chances to sit because 1

already selected

in 3rd place there are 4 chances to sit

thus multiply all 6×5×4=120

2) 20 numbers start from digit 2 thus there are 6 digits, from which 2 and 3 are less than 4

so they 2 numbers (2, 3) multiply by 20 to give no less

than 400

=20×2=40

3) (2 and 6) are two different even numbers

total no =120

and 20 (3 digit) numbers of each no from last

and (2,6) are 2 even no

so 20×2=40

4) odd = total - even

odd = 120 - 40

= 80 no

above question of D part is not o but it is odd

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