Question

If retardation produced by air resistance
of projectile is one-tenth of acceleration
due to gravity, the time to reach
maximum height
​

Answer 1

Answer:

Increased by 9%.

Given-

The retardation is produced by retardation is 1/10.

To find-

time to reach the maximum height=?

Solution-

By first equation of motion,

⇒$v=u+at$

⨳Here, v=final velocity

u= initial velocity

a= acceleration due to gravity

t= tike taken

$0=usin\theta-(\frac{11g}{10} )t$

$t=\frac{ 10usin\theta}{11g}$

so, the decrecement is given as $\frac{\frac{ usin\theta}{g} -\frac{ 10usin\theta}{11g} }{\frac{usin\theta}{g} }$ ⨉ 100

$\frac{1}{11} *100 = 9$%

Explanation: