Math, asked by navatej15, 9 months ago

.If Roopa was younger by 5 years than what she really is, then square of her age (in

years) would have been 11 more than five times her actual age. What is her age

now?

Answers

Answered by masterstroke360
4

Answer:

Roopa's present age is equal to 14 years.

Step-by-step explanation:

Let Roopa's present age be equal to x.

Her age five years before from today = x - 5

Given the square of her age five years earlier is 11 more than 5 times her actual age.

(x - 5)² = 5x + 11

Solving the equation to find the value of x .

=> x² + 25 - 10x = 5x + 11

=> x² -15x +14 = 0

=> x² -14x - x + 14 = 0

=> x(x-14) -1(x-14) = 0

=> x = 14 , 1

So the present age of Roopa is 14 years.

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Answered by harmanshergill
3

Answer:

the present age of Roopa is 14 years

Step-by-step explanation:

let the present age of Roopa = x

5 years ago Roopa's age = x-5

according to the question ,

(x-5)² = 5x +11

x² + 25 -10x = 5x+ 11

x² -15x + 14 =0

x² -14x -x +14 = 0

x(x- 14) -1 (x-14) = 0

(x-14)(x-1) = 0

either ; x= 1

or x= 14

bt x= 1 is not possible

thus x= 14

so; the present age of Roopa is 14 years

Thanks

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