Question

if root 11-1/ root 11 + 1 =a-b root 11, then find the value of a and b​

Answer 1

√11-√1/√11+√1=a-B(√11)

LHS

√11-1/√11+1×√11-1/√11-1

(√11-1)²/(√11)²-(1)²

(√11)²+1-2(√11)/11-1

11+1-2(√11)/10

12-2(√11)/10

LHS=RHS

12-2(√11)/10=a-B(√11)

a=12/10;b=2/10

therefore a=6/5;b=1/5

Answer 2

The value of a = 1 and b = 1/5.

The following is a simpler version of the given expression:

root(11) - 1 / root(11) + 1

= (root(11)-1)/(root(11)+1) * (root(11)-1)/(root(11)-1)

= (11 - 2root(11) + 1) / (11 - 1)

= (10 - 2root(11)) / 10

Now we can equate this expression to a - b root(11) and solve for a and b:

(10 - 2root(11)) / 10 = a - b root(11)

Multiplying both sides by 10 and rearranging, we get:

10a - 10b root(11) = 10 - 2root(11)

Now we can equate the coefficients of root(11) and the constant terms on both sides:

10a = 10

-10b = -2

Solving these equations, we get:

a = 1

b = 1/5

Therefore, a = 1 and b = 1/5.

For such more questions on value,

https://brainly.in/question/48714416

#SPJ3