If (root 2)^x + (root 3)^x = (root 13)^x/2, then the value of x is olymipiad class 9 maths
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Step-by-step explanation:
We know that , 13 = 4+9 (13−−√)2=( 4√)2+(9√)2(13−−√)2=( 2√)4+(3√)4(13−−√)42=( 2√)4+(3√)4. Comparing it with(13−−√)x2=( 2√)x+(3√)x. We get x =4
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